printf("\nNumber of command line arguments : %d", argc);
06
07
for( i = 0 ; i < argc ; i ++ ) {
08
printf("\nArgument[%d]: %s", i, argv[i]);
09
}
10
11
getch();
12
}
BE_THE_CODER_C.exe ONE TWO THREE It gives the following output,
Number of command line arguments : 4
Argument[0]: C:\BE_THE_CODER\BE_THE_CODER_C\BE_THE_CODER_C.exe
Argument[1]: ONE
Argument[2]: TWO
Argument[3]: THREE