This example shows simple application of pointer arithmetic.
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#include<stdio.h>
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#include<conio.h>
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int
main()
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{
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char
*s =
"BETHECODER"
;
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printf
(
"%s\n"
, s++);
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getch();
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return
0;
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}
BETHECODER ETHECODER THECODER HECODER ECODER CODER